Optimal. Leaf size=147 \[ -\frac {b^2 \log \left (\frac {2}{1+i c x^3}\right ) \left (a+b \tan ^{-1}\left (c x^3\right )\right )}{c^2}+\frac {\left (a+b \tan ^{-1}\left (c x^3\right )\right )^3}{6 c^2}-\frac {i b \left (a+b \tan ^{-1}\left (c x^3\right )\right )^2}{2 c^2}-\frac {b x^3 \left (a+b \tan ^{-1}\left (c x^3\right )\right )^2}{2 c}+\frac {1}{6} x^6 \left (a+b \tan ^{-1}\left (c x^3\right )\right )^3-\frac {i b^3 \text {Li}_2\left (1-\frac {2}{i c x^3+1}\right )}{2 c^2} \]
[Out]
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Rubi [B] time = 4.73, antiderivative size = 951, normalized size of antiderivative = 6.47, number of steps used = 155, number of rules used = 30, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.875, Rules used = {5035, 2454, 2401, 2389, 2296, 2295, 2390, 2305, 2304, 2439, 2416, 2396, 2433, 2374, 6589, 2411, 43, 2334, 12, 14, 2301, 6742, 2395, 2394, 2393, 2391, 2375, 2317, 2430, 2425} \[ \frac {1}{16} i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (i c x^3+1\right ) x^6+\frac {1}{16} i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (i c x^3+1\right ) x^6+\frac {b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (i c x^3+1\right ) x^3}{4 c}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {i b^3 \left (i c x^3+1\right )^2 \log ^3\left (i c x^3+1\right )}{48 c^2}+\frac {i b^3 \left (i c x^3+1\right ) \log ^3\left (i c x^3+1\right )}{24 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{32 c^2}-\frac {i b \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{8 c^2}-\frac {i b^3 \left (i c x^3+1\right ) \log ^2\left (i c x^3+1\right )}{8 c^2}-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \log ^2\left (i c x^3+1\right )}{16 c^2}+\frac {i b^2 \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{32 c^2}+\frac {b^2 \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )}{32 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (i c x^3+1\right )\right )}{16 c^2}+\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (i c x^3+1\right )\right )}{16 c^2}-\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (i c x^3+1\right )\right )}{4 c^2}-\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (i c x^3+1\right )}{16 c^2}-\frac {i b^3 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (i c x^3+1\right )}{4 c^2}-\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \text {PolyLog}\left (2,\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \text {PolyLog}\left (2,\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}+\frac {i b^3 \text {PolyLog}\left (2,\frac {1}{2} \left (1-i c x^3\right )\right )}{4 c^2}-\frac {i b^3 \text {PolyLog}\left (2,\frac {1}{2} \left (i c x^3+1\right )\right )}{4 c^2} \]
Warning: Unable to verify antiderivative.
[In]
[Out]
Rule 12
Rule 14
Rule 43
Rule 2295
Rule 2296
Rule 2301
Rule 2304
Rule 2305
Rule 2317
Rule 2334
Rule 2374
Rule 2375
Rule 2389
Rule 2390
Rule 2391
Rule 2393
Rule 2394
Rule 2395
Rule 2396
Rule 2401
Rule 2411
Rule 2416
Rule 2425
Rule 2430
Rule 2433
Rule 2439
Rule 2454
Rule 5035
Rule 6589
Rule 6742
Rubi steps
\begin {align*} \int x^5 \left (a+b \tan ^{-1}\left (c x^3\right )\right )^3 \, dx &=\int \left (\frac {1}{8} x^5 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3+\frac {3}{8} i b x^5 \left (-2 i a+b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {3}{8} i b^2 x^5 \left (-2 i a+b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )+\frac {1}{8} i b^3 x^5 \log ^3\left (1+i c x^3\right )\right ) \, dx\\ &=\frac {1}{8} \int x^5 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3 \, dx+\frac {1}{8} (3 i b) \int x^5 \left (-2 i a+b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right ) \, dx-\frac {1}{8} \left (3 i b^2\right ) \int x^5 \left (-2 i a+b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right ) \, dx+\frac {1}{8} \left (i b^3\right ) \int x^5 \log ^3\left (1+i c x^3\right ) \, dx\\ &=\frac {1}{24} \operatorname {Subst}\left (\int x (2 a+i b \log (1-i c x))^3 \, dx,x,x^3\right )+\frac {1}{8} (i b) \operatorname {Subst}\left (\int x (-2 i a+b \log (1-i c x))^2 \log (1+i c x) \, dx,x,x^3\right )-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int x (-2 i a+b \log (1-i c x)) \log ^2(1+i c x) \, dx,x,x^3\right )+\frac {1}{24} \left (i b^3\right ) \operatorname {Subst}\left (\int x \log ^3(1+i c x) \, dx,x,x^3\right )\\ &=\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )+\frac {1}{24} \operatorname {Subst}\left (\int \left (-\frac {i (2 a+i b \log (1-i c x))^3}{c}+\frac {i (1-i c x) (2 a+i b \log (1-i c x))^3}{c}\right ) \, dx,x,x^3\right )+\frac {1}{24} \left (i b^3\right ) \operatorname {Subst}\left (\int \left (\frac {i \log ^3(1+i c x)}{c}-\frac {i (1+i c x) \log ^3(1+i c x)}{c}\right ) \, dx,x,x^3\right )+\frac {1}{16} (b c) \operatorname {Subst}\left (\int \frac {x^2 (-2 i a+b \log (1-i c x))^2}{1+i c x} \, dx,x,x^3\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^2 (-2 i a+b \log (1-i c x)) \log (1+i c x)}{1-i c x} \, dx,x,x^3\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \frac {x^2 (-2 i a+b \log (1-i c x)) \log (1+i c x)}{1+i c x} \, dx,x,x^3\right )+\frac {1}{16} \left (b^3 c\right ) \operatorname {Subst}\left (\int \frac {x^2 \log ^2(1+i c x)}{1-i c x} \, dx,x,x^3\right )\\ &=\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {i \operatorname {Subst}\left (\int (2 a+i b \log (1-i c x))^3 \, dx,x,x^3\right )}{24 c}+\frac {i \operatorname {Subst}\left (\int (1-i c x) (2 a+i b \log (1-i c x))^3 \, dx,x,x^3\right )}{24 c}-\frac {b^3 \operatorname {Subst}\left (\int \log ^3(1+i c x) \, dx,x,x^3\right )}{24 c}+\frac {b^3 \operatorname {Subst}\left (\int (1+i c x) \log ^3(1+i c x) \, dx,x,x^3\right )}{24 c}+\frac {1}{16} (b c) \operatorname {Subst}\left (\int \left (\frac {(-2 i a+b \log (1-i c x))^2}{c^2}-\frac {i x (-2 i a+b \log (1-i c x))^2}{c}+\frac {i (-2 i a+b \log (1-i c x))^2}{c^2 (-i+c x)}\right ) \, dx,x,x^3\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (-\frac {x (2 a+i b \log (1-i c x)) \log (1+i c x)}{c}+\frac {(2 a+i b \log (1-i c x)) \log (1+i c x)}{c^2 (-i+c x)}+\frac {(-2 i a+b \log (1-i c x)) \log (1+i c x)}{c^2}\right ) \, dx,x,x^3\right )-\frac {1}{8} \left (b^2 c\right ) \operatorname {Subst}\left (\int \left (\frac {x (2 a+i b \log (1-i c x)) \log (1+i c x)}{c}-\frac {(2 a+i b \log (1-i c x)) \log (1+i c x)}{c^2 (i+c x)}+\frac {(-2 i a+b \log (1-i c x)) \log (1+i c x)}{c^2}\right ) \, dx,x,x^3\right )+\frac {1}{16} \left (b^3 c\right ) \operatorname {Subst}\left (\int \left (\frac {\log ^2(1+i c x)}{c^2}+\frac {i x \log ^2(1+i c x)}{c}-\frac {i \log ^2(1+i c x)}{c^2 (i+c x)}\right ) \, dx,x,x^3\right )\\ &=\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {1}{16} (i b) \operatorname {Subst}\left (\int x (-2 i a+b \log (1-i c x))^2 \, dx,x,x^3\right )+\frac {1}{16} \left (i b^3\right ) \operatorname {Subst}\left (\int x \log ^2(1+i c x) \, dx,x,x^3\right )+\frac {\operatorname {Subst}\left (\int (2 a+i b \log (x))^3 \, dx,x,1-i c x^3\right )}{24 c^2}-\frac {\operatorname {Subst}\left (\int x (2 a+i b \log (x))^3 \, dx,x,1-i c x^3\right )}{24 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log ^3(x) \, dx,x,1+i c x^3\right )}{24 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int x \log ^3(x) \, dx,x,1+i c x^3\right )}{24 c^2}+\frac {(i b) \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x))^2}{-i+c x} \, dx,x,x^3\right )}{16 c}+\frac {b \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x))^2 \, dx,x,x^3\right )}{16 c}-\frac {b^2 \operatorname {Subst}\left (\int \frac {(2 a+i b \log (1-i c x)) \log (1+i c x)}{-i+c x} \, dx,x,x^3\right )}{8 c}+\frac {b^2 \operatorname {Subst}\left (\int \frac {(2 a+i b \log (1-i c x)) \log (1+i c x)}{i+c x} \, dx,x,x^3\right )}{8 c}-2 \frac {b^2 \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x)) \log (1+i c x) \, dx,x,x^3\right )}{8 c}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^2(1+i c x)}{i+c x} \, dx,x,x^3\right )}{16 c}+\frac {b^3 \operatorname {Subst}\left (\int \log ^2(1+i c x) \, dx,x,x^3\right )}{16 c}\\ &=\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {i b^3 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )+\frac {i b^3 \left (1+i c x^3\right ) \log ^3\left (1+i c x^3\right )}{24 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log ^3\left (1+i c x^3\right )}{48 c^2}-\frac {1}{16} (i b) \operatorname {Subst}\left (\int \left (-\frac {i (-2 i a+b \log (1-i c x))^2}{c}+\frac {i (1-i c x) (-2 i a+b \log (1-i c x))^2}{c}\right ) \, dx,x,x^3\right )+\frac {1}{16} \left (i b^3\right ) \operatorname {Subst}\left (\int \left (\frac {i \log ^2(1+i c x)}{c}-\frac {i (1+i c x) \log ^2(1+i c x)}{c}\right ) \, dx,x,x^3\right )-2 \left (-\frac {b^2 x^3 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c}-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \frac {x (-2 i a+b \log (1-i c x))}{1+i c x} \, dx,x,x^3\right )+\frac {1}{8} \left (i b^3\right ) \operatorname {Subst}\left (\int \frac {x \log (1+i c x)}{1-i c x} \, dx,x,x^3\right )\right )+\frac {(i b) \operatorname {Subst}\left (\int x (2 a+i b \log (x))^2 \, dx,x,1-i c x^3\right )}{16 c^2}+\frac {(i b) \operatorname {Subst}\left (\int (-2 i a+b \log (x))^2 \, dx,x,1-i c x^3\right )}{16 c^2}-\frac {(i b) \operatorname {Subst}\left (\int (2 a+i b \log (x))^2 \, dx,x,1-i c x^3\right )}{8 c^2}-\frac {b^2 \operatorname {Subst}\left (\int \frac {(2 a+i b \log (2-x)) \log (x)}{x} \, dx,x,1+i c x^3\right )}{8 c^2}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log (2-x) (2 a+i b \log (x))}{x} \, dx,x,1-i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log ^2(x) \, dx,x,1+i c x^3\right )}{16 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int x \log ^2(x) \, dx,x,1+i c x^3\right )}{16 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log ^2(x) \, dx,x,1+i c x^3\right )}{8 c^2}-\frac {b^2 \operatorname {Subst}\left (\int \frac {(-2 i a+b \log (1-i c x)) \log \left (\frac {1}{2} i (-i+c x)\right )}{1-i c x} \, dx,x,x^3\right )}{8 c}-\frac {b^3 \operatorname {Subst}\left (\int \frac {\log (1+i c x) \log \left (-\frac {1}{2} i (i+c x)\right )}{1+i c x} \, dx,x,x^3\right )}{8 c}\\ &=\frac {i b \left (1-i c x^3\right ) \left (2 i a-b \log \left (1-i c x^3\right )\right )^2}{16 c^2}-\frac {i b \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{8 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{16 c^2}-\frac {3 i b^3 \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right )^2 \log ^2\left (1+i c x^3\right )}{32 c^2}-\frac {i b^3 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log ^3\left (1+i c x^3\right )}{24 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log ^3\left (1+i c x^3\right )}{48 c^2}-2 \left (-\frac {b^2 x^3 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c}-\frac {1}{8} \left (i b^2\right ) \operatorname {Subst}\left (\int \left (-\frac {i (-2 i a+b \log (1-i c x))}{c}+\frac {-2 i a+b \log (1-i c x)}{c (-i+c x)}\right ) \, dx,x,x^3\right )+\frac {1}{8} \left (i b^3\right ) \operatorname {Subst}\left (\int \left (\frac {i \log (1+i c x)}{c}+\frac {\log (1+i c x)}{c (i+c x)}\right ) \, dx,x,x^3\right )\right )-\frac {(i b) \operatorname {Subst}\left (\int \frac {(2 a+i b \log (x))^2}{2-x} \, dx,x,1-i c x^3\right )}{16 c^2}-\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int (-2 i a+b \log (x)) \, dx,x,1-i c x^3\right )}{8 c^2}-\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \frac {\log \left (\frac {1}{2} i (-2 i+i x)\right ) (-2 i a+b \log (x))}{x} \, dx,x,1-i c x^3\right )}{8 c^2}+\frac {b^2 \operatorname {Subst}\left (\int x (2 a+i b \log (x)) \, dx,x,1-i c x^3\right )}{16 c^2}-\frac {b^2 \operatorname {Subst}\left (\int (2 a+i b \log (x)) \, dx,x,1-i c x^3\right )}{4 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int x \log (x) \, dx,x,1+i c x^3\right )}{16 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log ^2(x)}{2-x} \, dx,x,1+i c x^3\right )}{16 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1+i c x^3\right )}{8 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {1}{2} i (2 i-i x)\right ) \log (x)}{x} \, dx,x,1+i c x^3\right )}{8 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1+i c x^3\right )}{4 c^2}-\frac {b \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x))^2 \, dx,x,x^3\right )}{16 c}+\frac {b \operatorname {Subst}\left (\int (1-i c x) (-2 i a+b \log (1-i c x))^2 \, dx,x,x^3\right )}{16 c}-\frac {b^3 \operatorname {Subst}\left (\int \log ^2(1+i c x) \, dx,x,x^3\right )}{16 c}+\frac {b^3 \operatorname {Subst}\left (\int (1+i c x) \log ^2(1+i c x) \, dx,x,x^3\right )}{16 c}\\ &=\frac {3 i a b^2 x^3}{4 c}+\frac {3 b^3 x^3}{8 c}-\frac {i b^3 \left (1-i c x^3\right )^2}{64 c^2}+\frac {i b^3 \left (1+i c x^3\right )^2}{64 c^2}+\frac {i b \left (1-i c x^3\right ) \left (2 i a-b \log \left (1-i c x^3\right )\right )^2}{16 c^2}+\frac {b^2 \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )}{32 c^2}-\frac {i b \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{8 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {3 i b^3 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{8 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log \left (1+i c x^3\right )}{32 c^2}+\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{16 c^2}-\frac {3 i b^3 \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right )^2 \log ^2\left (1+i c x^3\right )}{32 c^2}+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log ^3\left (1+i c x^3\right )}{24 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log ^3\left (1+i c x^3\right )}{48 c^2}-\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-\frac {i b^3 \log \left (1+i c x^3\right ) \text {Li}_2\left (\frac {1}{2} \left (1+i c x^3\right )\right )}{8 c^2}-\frac {(i b) \operatorname {Subst}\left (\int (-2 i a+b \log (x))^2 \, dx,x,1-i c x^3\right )}{16 c^2}+\frac {(i b) \operatorname {Subst}\left (\int x (-2 i a+b \log (x))^2 \, dx,x,1-i c x^3\right )}{16 c^2}+\frac {b^2 \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right ) (2 a+i b \log (x))}{x} \, dx,x,1-i c x^3\right )}{8 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log ^2(x) \, dx,x,1+i c x^3\right )}{16 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int x \log ^2(x) \, dx,x,1+i c x^3\right )}{16 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1-i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right ) \log (x)}{x} \, dx,x,1+i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1-i c x^3\right )}{8 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1+i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1-i c x^3\right )}{4 c^2}-2 \left (-\frac {b^2 x^3 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c}-\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int \frac {-2 i a+b \log (1-i c x)}{-i+c x} \, dx,x,x^3\right )}{8 c}-\frac {b^2 \operatorname {Subst}\left (\int (-2 i a+b \log (1-i c x)) \, dx,x,x^3\right )}{8 c}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log (1+i c x)}{i+c x} \, dx,x,x^3\right )}{8 c}-\frac {b^3 \operatorname {Subst}\left (\int \log (1+i c x) \, dx,x,x^3\right )}{8 c}\right )\\ &=\frac {3 i a b^2 x^3}{4 c}+\frac {3 b^3 x^3}{4 c}-\frac {i b^3 \left (1-i c x^3\right )^2}{64 c^2}+\frac {i b^3 \left (1+i c x^3\right )^2}{64 c^2}-\frac {3 i b^3 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{8 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {b^2 \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )}{32 c^2}-\frac {i b \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{8 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {3 i b^3 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{8 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log \left (1+i c x^3\right )}{32 c^2}+\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{16 c^2}-\frac {i b^3 \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{8 c^2}+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log ^3\left (1+i c x^3\right )}{24 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log ^3\left (1+i c x^3\right )}{48 c^2}-\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-\frac {i b^3 \text {Li}_3\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}+\frac {i b^3 \text {Li}_3\left (\frac {1}{2} \left (1+i c x^3\right )\right )}{8 c^2}-\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int x (-2 i a+b \log (x)) \, dx,x,1-i c x^3\right )}{16 c^2}+\frac {\left (i b^2\right ) \operatorname {Subst}\left (\int (-2 i a+b \log (x)) \, dx,x,1-i c x^3\right )}{8 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int x \log (x) \, dx,x,1+i c x^3\right )}{16 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1+i c x^3\right )}{8 c^2}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1-i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\text {Li}_2\left (\frac {x}{2}\right )}{x} \, dx,x,1+i c x^3\right )}{8 c^2}-2 \left (\frac {i a b^2 x^3}{4 c}+\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{8 c^2}+\frac {i b^3 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c^2}-\frac {b^2 x^3 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1+i c x^3\right )}{8 c^2}-\frac {b^3 \operatorname {Subst}\left (\int \log (1-i c x) \, dx,x,x^3\right )}{8 c}+\frac {b^3 \operatorname {Subst}\left (\int \frac {\log \left (\frac {1}{2} i (-i+c x)\right )}{1-i c x} \, dx,x,x^3\right )}{8 c}+\frac {b^3 \operatorname {Subst}\left (\int \frac {\log \left (-\frac {1}{2} i (i+c x)\right )}{1+i c x} \, dx,x,x^3\right )}{8 c}\right )\\ &=\frac {i a b^2 x^3}{2 c}+\frac {5 b^3 x^3}{8 c}-\frac {3 i b^3 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{8 c^2}+\frac {i b^2 \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{32 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {b^2 \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )}{32 c^2}-\frac {i b \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{8 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{4 c^2}+\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{16 c^2}-\frac {i b^3 \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{8 c^2}+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log ^3\left (1+i c x^3\right )}{24 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log ^3\left (1+i c x^3\right )}{48 c^2}-\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-2 \left (\frac {i a b^2 x^3}{4 c}+\frac {b^3 x^3}{8 c}+\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{8 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{8 c^2}+\frac {i b^3 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c^2}-\frac {b^2 x^3 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c}+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right )}{x} \, dx,x,1-i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {x}{2}\right )}{x} \, dx,x,1+i c x^3\right )}{8 c^2}-\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1-i c x^3\right )}{8 c^2}\right )+\frac {\left (i b^3\right ) \operatorname {Subst}\left (\int \log (x) \, dx,x,1-i c x^3\right )}{8 c^2}\\ &=\frac {i a b^2 x^3}{2 c}+\frac {b^3 x^3}{2 c}-\frac {i b^3 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{4 c^2}+\frac {i b^2 \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )}{32 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {b^2 \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )}{32 c^2}-\frac {i b \left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{8 c^2}+\frac {i b \left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^2}{32 c^2}+\frac {\left (1-i c x^3\right ) \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{24 c^2}-\frac {\left (1-i c x^3\right )^2 \left (2 a+i b \log \left (1-i c x^3\right )\right )^3}{48 c^2}+\frac {i b \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{4 c^2}+\frac {1}{16} i b x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )-\frac {i b \left (2 a+i b \log \left (1-i c x^3\right )\right )^2 \log \left (1+i c x^3\right )}{16 c^2}-\frac {i b^3 \left (1+i c x^3\right ) \log ^2\left (1+i c x^3\right )}{8 c^2}+\frac {1}{16} i b^2 x^6 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \log ^2\left (1+i c x^3\right )}{16 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log ^3\left (1+i c x^3\right )}{24 c^2}-\frac {i b^3 \left (1+i c x^3\right )^2 \log ^3\left (1+i c x^3\right )}{48 c^2}-\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-\frac {b^2 \left (2 a+i b \log \left (1-i c x^3\right )\right ) \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}-2 \left (\frac {i a b^2 x^3}{4 c}+\frac {b^3 x^3}{4 c}-\frac {i b^3 \left (1-i c x^3\right ) \log \left (1-i c x^3\right )}{8 c^2}+\frac {i b^2 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (\frac {1}{2} \left (1+i c x^3\right )\right )}{8 c^2}+\frac {i b^3 \left (1+i c x^3\right ) \log \left (1+i c x^3\right )}{8 c^2}+\frac {i b^3 \log \left (\frac {1}{2} \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c^2}-\frac {b^2 x^3 \left (2 i a-b \log \left (1-i c x^3\right )\right ) \log \left (1+i c x^3\right )}{8 c}-\frac {i b^3 \text {Li}_2\left (\frac {1}{2} \left (1-i c x^3\right )\right )}{8 c^2}+\frac {i b^3 \text {Li}_2\left (\frac {1}{2} \left (1+i c x^3\right )\right )}{8 c^2}\right )\\ \end {align*}
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Mathematica [A] time = 0.18, size = 170, normalized size = 1.16 \[ \frac {a \left (a c x^3 \left (a c x^3-3 b\right )+3 b^2 \log \left (c^2 x^6+1\right )\right )+3 b^2 \tan ^{-1}\left (c x^3\right )^2 \left (a c^2 x^6+a+b \left (-c x^3+i\right )\right )+3 b \tan ^{-1}\left (c x^3\right ) \left (a \left (a c^2 x^6+a-2 b c x^3\right )-2 b^2 \log \left (1+e^{2 i \tan ^{-1}\left (c x^3\right )}\right )\right )+b^3 \left (c^2 x^6+1\right ) \tan ^{-1}\left (c x^3\right )^3+3 i b^3 \text {Li}_2\left (-e^{2 i \tan ^{-1}\left (c x^3\right )}\right )}{6 c^2} \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.45, size = 0, normalized size = 0.00 \[ {\rm integral}\left (b^{3} x^{5} \arctan \left (c x^{3}\right )^{3} + 3 \, a b^{2} x^{5} \arctan \left (c x^{3}\right )^{2} + 3 \, a^{2} b x^{5} \arctan \left (c x^{3}\right ) + a^{3} x^{5}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (b \arctan \left (c x^{3}\right ) + a\right )}^{3} x^{5}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 1.78, size = 867, normalized size = 5.90 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {1}{2} \, a b^{2} x^{6} \arctan \left (c x^{3}\right )^{2} + \frac {1}{6} \, a^{3} x^{6} + \frac {1}{2} \, {\left (x^{6} \arctan \left (c x^{3}\right ) - c {\left (\frac {x^{3}}{c^{2}} - \frac {\arctan \left (c x^{3}\right )}{c^{3}}\right )}\right )} a^{2} b - \frac {1}{2} \, {\left (2 \, c {\left (\frac {x^{3}}{c^{2}} - \frac {\arctan \left (c x^{3}\right )}{c^{3}}\right )} \arctan \left (c x^{3}\right ) + \frac {\arctan \left (c x^{3}\right )^{2} - \log \left (6 \, c^{5} x^{6} + 6 \, c^{3}\right )}{c^{2}}\right )} a b^{2} + \frac {1}{192} \, {\left (4 \, x^{6} \arctan \left (c x^{3}\right )^{3} - 3 \, x^{6} \arctan \left (c x^{3}\right ) \log \left (c^{2} x^{6} + 1\right )^{2} + 192 \, \int \frac {12 \, c^{2} x^{11} \arctan \left (c x^{3}\right ) \log \left (c^{2} x^{6} + 1\right ) - 12 \, c x^{8} \arctan \left (c x^{3}\right )^{2} + 56 \, {\left (c^{2} x^{11} + x^{5}\right )} \arctan \left (c x^{3}\right )^{3} + 3 \, {\left (c x^{8} + 2 \, {\left (c^{2} x^{11} + x^{5}\right )} \arctan \left (c x^{3}\right )\right )} \log \left (c^{2} x^{6} + 1\right )^{2}}{64 \, {\left (c^{2} x^{6} + 1\right )}}\,{d x}\right )} b^{3} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int x^5\,{\left (a+b\,\mathrm {atan}\left (c\,x^3\right )\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{5} \left (a + b \operatorname {atan}{\left (c x^{3} \right )}\right )^{3}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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